I will be in the fifth floor common room tomorrow from 4-5 PM to answer last minute questions.
3704
May 17, 2009
A subtle question about principality
Posted by minhyong kim under 3704, number theoryLeave a Comment
Dear Professor Kim,
I just have a few small questions. In lectures, we calculated the class group of , which has ring of algebraic integers
. We then found that that (maximal ideal)
,
After a bunch of calculations we had to see whether was principal or not. Using the result,
—————————————————————-
(non-zero) is principal iff there exists
s.t
—————————————————————–
We had to consider if there was s.t
Since the general element of the ideal is
, is it ‘more correct’ to consider if there was
s.t
I know this doesn’t make a whole lot of difference, it’s just one of those things.
So
which was equivalent to the statement
or
In general, do we consider any ‘modulo n’ so that the statement is simplified?
Many Thanks
———————————————————
Reply:
You are absolutely right about the principality question. That is, when we have an ideal in the ring of integers
of an algebraic number field
such that
, then we are led to consider solutions to the equation
for various . As we’ve seen in many examples, once
is expressed in terms of an integral basis, this becomes an equation in
variables with integer coefficients to which we can consider solutions. Now, if there are no solutions with
, then, a fortiori, there are no solutions
and we can conclude that
is not principal. However, although I’m too lazy now to cook up an example, there are situations where there *is* a solution
, but no solution
. In the example you mention, the equation corresponding to
is easily found to be
which is obviously more resrictive than
In our case, the latter already has no solution, so we don’t need to consider the more refined equation.
Regarding your second question, firstly, the equation is not *equivalent* to the congruence equation but just implies it. So if the congruence equation has no solution, neither does the original, which is how we used it. Now, I don’t quite understand your final question, but perhaps I should remark that considering congruences is a standard way of investigating solutions to quadratic equations. In fact, it is useful for *any* Diophantine equation. However, a rather deep theorem says that for quadratic equations, sufficiently many congruence equations completely determine whether or not the original equation has rational solutions.
May 17, 2009
Dear Dr Kim,
There is a post on your blog regarding finding primitive elements. Your advice was to look at the Primitive elements: an example document. Can I assume this would be an acceptable answer in the exam and, would just stating that the method is the same as the one used for proving the Primitive Element Theorem be sufficient justification or do we need to provide further explanation?
Thanks in advance,
———————————————————-
Reply:
Of course the method is acceptable, but I don’t understand what you mean by `sufficient justification.’
Let’s remind ourselves what method we are speaking of:
To find a primitive element in , we need to locate a linear combination
with
satisfying certain conditions spelled out in the proof of the Primitive Element Theorem. It might be
,
,
, etc. depending on the situation, even though the result tends to be rather simple in the examples that have come up. To use the method of the theorem would mean checking that the conditions are satified for some specific
. If you did this, yes it would be sufficient justification.
May 16, 2009
Sorry to bombard you with my problems professor, but i was attempting problem sheet 6 in a bid to understand how to calculate class groups properly, and have no real problem with it up until the point where we start to deduce which of the prime ideals are principal. When i say prime ideals i hope i’m right in calling the curly p with subscript of a prime number that. If the norm of a general element is a prime we say that the prime ideal is maximal right? I was attempting question one for root 11 and the one step i seem to have difficulty with is when we calculate the other norms of and above, i have a vague understanding of what we do where we assign the norms to the prime ideals depending on what they are. But this step in general seems to allude me whenever i attempt these questions. So if you could shed some light on this step or could just guide me to the theorems or lemmas that would help with this area that would be extremely helpful. Thanks
———————————————————–
Reply:
I’m sorry to say this so close to the exam, but some of your questions are a bit worrisome. For example, the question `If the norm of a general element is a prime we say that the prime ideal is maximal right?’. It’s hard to make out what you mean. A correct statement is that inside the ring of integers inside an algebraic number field
, all non-zero prime ideals are maximal. This fact is actually a bit tricky: it follows from the fact that
is finite for any non-zero ideal
and that any finite integral domain is a field. I hope you’re not confused about the *definition* of prime and maximal ideals, which just come from general algebra.
Let me guess a bit at what the confusion might be. When factorizing an ideal , very relevant are the prime factors of
. This is because if
then
We know in fact that each will be a prime power factor of
. This allows us to look for prime ideal factors of
.
I hope you’ve already thoroughly reviewed the online notes. Chapter 4 is the relevant part for this material.
May 16, 2009
Hi professor,
I was just wandering in the 2007 paper when it says from first principles to determine the ring of algebraic integers in , what this actually means, hope it doesn’t sound like a dumb question. Do we just bear in mind the definition of an algebraic integer and produce a basis for
and show that for any element
that
and
are integers?
As regards with the previous question i think the was more like
.
Thanks
—————————————————————————-
Reply:
In essence, yes. A general element of is of the form
for
. In that problem, you are expected to show that
is an algebraic integer if and only if
, using just the definition. The context of the problem might help you to understand what is expected from the solution: I noticed at some point that there were students who knew the (important!) formula for the ring of integers in general
and could justify it, but then got awfully confused when presented with the same problem for specific
.
By the way, to defend my notation , note that there are two different ways to insert brackets, both leading to the same subgroups of
. Hence, it’s OK to omit them
.
May 15, 2009
Integers, class groups, multiplying ideals…
Posted by minhyong kim under 3704, number theoryLeave a Comment
Many thanks, that wasn’t meant to sound like quite such a leading questions, I think I was in the midst of exam panic when I sent it! Sorry to fire off another list of questions, I’m fully aware that you must be inundated with emails at this time of year, so thank you again for being so prompt and clear in your responses!
1) In the 2008 exam qu1 part d: Is it possible to just calculate the minimal polynomial and see if the degree is the same as the extension?
2) In A Few Past Exam questions:
The discriminant in the second part is given as , no matter how many different methods I use to calculate this I don’t get the right answer! I was using the assumption that as a cubic we can use
but this gives me
?
3) How do we multiply maximal ideals explicitly? For example in ‘A few past exam questions’ I can see how this is true for but do we then just deduce
or is their some way of calculating this? I can also see that an alternative factorization could be as
but again don’t see how to explicitly calculate the second result.
4) In Integral Bases and Translations: The discriminant of B is given as , is this correct? My calculations gave me either
or equivalently
5) In Few Class Groups:
How do we know the ring of algebraic integers is ? When calculating I get a possible algebraic integer with prime 2 (which is eliminated using Eisenstein) but am still left with prime 3 giving the possibility of algebraic integer
Kindest regards,
—————————————————————
Reply:
(1) Yes, it’s fine to do this. Another way is to use the proof of the primitive element theorem, as explained in `Primitive elements: an example.’
(2) You are right! That was a silly error on my part. Thankfully, it doesn’t affect the rest of the argument at all, so it went unnoticed.
(3) Multiplying explicitly isn’t too hard by just multiplying the generators. For example, in the case of and
, we would get
But that isn’t how I obtained the formula you mention. It would have been a bit tricky to guess the generator just from the presentation above. What I actually did was factorize
. Since
, then only possibilities are
or
But it has to be the former since , so that
.
(4) In this case, I think I’m right (surprise, surprise). Just follow the computation in that article using .
(5) I’m supposing you mean the problem where . The point is that for the translation
, we get the irreducible polynomial
which is Eisenstein for the prime 3. Now follow the reasoning in `Integral bases and translations.
May 14, 2009
Norms of elements and principality
Posted by minhyong kim under 3704, algebra, number theory[2] Comments
Dear Professor Kim,
Sorry to bombard you with these questions. I have come across a problem on your note ’some principle ideals’. When we factorize modulo 3 we get
we then associate these factors with the ideals
and
respectively. When we compute the norm of
we do so by calculating the determinant of the matrix
and find that the norm is in fact 9, so
is a principle ideal. However, we could just have easily used
or
and in each case I get a different answer for the determinant. Have I made an error or is there a canonical form of sort that I should be aware of?
Thank you for your time.
———————————————-
Reply:
First of all, I presume your etc. are
etc. All the elements you mention do indeed belong to the ideal and can be used as generators *when used together with the element 3*. Indeed they are all all evaluations at
of polynomials that are congruent to
mod
. However, this does not mean they are generators on their own. Of course different elements in an ideal
will have different norms in general. However, an element
is a generator *by itself* (making
into a principal ideal), exactly when
. Of course such a
need not exist. I haven’t calculated the norms of the elements you mention, but if their norms come out larger than 9, it merely says they are not generators (again, by themselves), while
is.
A thorny point that comes out of this discussion is that if you had initially presented the ideal as , for example, then it might have been harder to see that it is principal.
May 14, 2009
Dear Professor Kim,
I am unsure of how to calculate the norm of in the ring
, which is on Sheet 5 Question 4a.
I can see that this ideal can be written as so it will have norm 4. Also, in the ring
a general element looks like
where
belong to $ latex Z$. So if we calculate the norm using the principle
From what I understand this is the reasoning you give in ‘Some remarks on factorization’.
However, if we use the method which given further down that sheet I get:
Please tell me where I’m going wrong.
Many Thanks!
—————————————————-
Reply:
first of all, I hope you can see that the line
above doesn’t make too much sense. The second displayed equation is almost right, except an error occurs when computing
Because the coefficients are in , we have
. So
from the isomorphism that takes
to
. It is easy to see that the
-vector space
has dimension 2 with basis
. Hence,
May 11, 2009
Hi Professor Kim hope you’re doing well. I just had a quick question to do with the notes on lecture 12 on the pdf file, in lecture 12 theres a ‘proof for the theorem’, I was just wandering is this an alternative proof for theorem 106? Or is it part of the same proof but just looking at the Norm of the derivative of the minimal polynomial?
—————————————————–
Reply:
I’m sorry. That portion of the notes is a bit disorganized. You are right that it is just an alternative proof. Thanks for pointing this out.
May 5, 2009
Hi Sir,
I have a few questions regarding the final exam:
1/. Will this years exam follow the same format of the test you set last year? i.e a stronger basis on method rather than proof.
2/. When looking at last years exam, I was unable to find the proof of question 1 part d in the notes. Where can I find the proof?
3/. Is it essential to learn the proof of dedekinds theorem for the exam?
4/. In last years exam, question 5, i.e calculating the class group, you said the class group was less than or equal to 6 where is this result from i.e the last paragraph of the answers.
Kindest Regards,
—————————————————————
Reply:
1. It’s difficult for me to give any precise answer to this question. I will just say that the overall distribution of types of problem will not differ too much from previous years. But you shuold remember my repeated warning that the notion of similarity in relation to a collection of problems needs to be understood rather generally, as happens when you have a sophisticated understanding of the material.
2. You should look at the article on primitive elements on the course webpage.
3. I can’t answer such a specific question. Dedekind’s Prime Factorization Theorem is certainly on the list of important theorems that I put in the summary.
4. For this question first I’ll ask you to read the previous portion of the proof very carefully. You can ask again if you’re completely stuck.